Advanced MathEasyHeight of a thrown ball
Advanced Math practice question
A ball's height in meters t seconds after being thrown is h(t) = 30t − 5t². What is the ball's height 2 seconds after the throw?
Answer: 40
h(2) = 30(2) − 5(2²) = 60 − 20 = 40 meters.
Common wrong answers
- If you answered 20
- 20 is the subtracted 5t² term; the height is 60 − 20 = 40.
- If you answered 50
- 5t² at t = 2 is 5 · 4 = 20, not 10.
- If you answered 60
- 60 is only the 30t part; subtract 5t² = 20.
More Advanced Math questions
- Easy
If f(x) = 3x − 7, what is the value of f(5)? - Easy
What are the solutions to x² − 9 = 0? - Easy
Which of the following expressions is equivalent to x² + 7x + 12 ? - Easy
The function g is defined by g(x) = x³ + 2x. What is the value of g(−2) ? - Easy
For x > 0, which of the following is equivalent to ∛(x⁵) ? - Easy
The function h is defined by h(x) = (x − 6)(x + 2). What is one value of x for which h(x) = 0 ?
Not affiliated with the College Board. SAT is a trademark of the College Board.