16Hit 1600
Advanced MathEasyHeight of a thrown ball

Advanced Math practice question

A ball's height in meters t seconds after being thrown is h(t) = 30t − 5t². What is the ball's height 2 seconds after the throw?

Answer: 40

h(2) = 30(2) − 5(2²) = 60 − 20 = 40 meters.

Common wrong answers

If you answered 20
20 is the subtracted 5t² term; the height is 60 − 20 = 40.
If you answered 50
5t² at t = 2 is 5 · 4 = 20, not 10.
If you answered 60
60 is only the 30t part; subtract 5t² = 20.

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