Advanced MathEasy–MediumUsing a known zero of a quadratic to find an unknown coefficient
Advanced Math practice question
The function h is defined by h(x) = x² + kx + 9, where k is a constant. If h(3) = 0, what is the value of k ?
Answer: -6
Substitute x = 3 into h: h(3) = 3² + k(3) + 9 = 9 + 3k + 9 = 18 + 3k. Setting this equal to 0 gives 3k = −18, so k = −6. (Check: x² − 6x + 9 = (x − 3)², which indeed has the zero x = 3.) The most common errors are (1) answering 6, which comes from solving 3k = 18 after moving 18 to the other side without changing its sign; (2) answering −3, which comes from dividing only the 9 from the constant term (9 + 3k = 0) and ignoring the 3² term; and (3) answering −18, which comes from stopping at 3k = −18 without dividing by 3.
Common wrong answers
- If you answered 6
- You moved 18 to the other side without changing its sign, solving 3k = 18; it should be 3k = −18, so k = −6.
- If you answered -3
- You set only 9 + 3k = 0 and ignored the 3² term; h(3) = 9 + 3k + 9 = 18 + 3k.
- If you answered -18
- You stopped at 3k = −18 — divide by 3 to get k = −6.
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