Advanced MathEasy–MediumLeast value in the range of a quadratic
Advanced Math practice question
The function f is defined by f(x) = x² + 1 for all real x. What is the least value in the range of f?
Answer: 1
x² is at least 0, so f(x) is at least 1, reached at x = 0.
Common wrong answers
- If you answered 0
- 0 is the least value of x², not of x² + 1.
- If you answered 2
- 2 is f(1), not the least value.
- If you answered -1
- −1 is below every value of f.
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- Easy–Medium
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For x ≠ 0, which expression is equivalent to (x² + 3x) / x? - Easy–Medium
What are the solutions to the equation 2(x − 3)² − 32 = 0 ?
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