Advanced MathEasyHeight of a thrown ball after one second
Advanced Math practice question
The height h, in metres, of a ball t seconds after it is thrown upward is h(t) = 20t − 5t². What is the height of the ball after 1 second?
Answer: 15
h(1) = 20 − 5 = 15.
Common wrong answers
- If you answered 5
- 5 is only the second term.
- If you answered 20
- 20 ignores the −5t² term.
- If you answered 25
- 25 adds the two terms instead of subtracting.
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