AlgebraHardSmallest of three consecutive integers from a condition
Algebra practice question
Twice the smallest of three consecutive integers is 6 more than the largest. What is the smallest of the three integers?
Answer: 8
With integers n, n + 1, n + 2: 2n = (n + 2) + 6, so n = 8.
Common wrong answers
- If you answered 4
- 4 halves 8.
- If you answered 6
- 6 comes from 2n = n + 6, forgetting the +2 of the largest.
- If you answered 10
- 10 is the largest.
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