AlgebraVery hardCounting possible purchases within a budget range
Algebra practice question
Chairs cost $30 each. A school will spend at least $600 and at most $800 on chairs, and it must spend a whole number of chairs' worth. How many different numbers of chairs could the school buy?
Answer: 7
600 ≤ 30c ≤ 800 gives 20 ≤ c ≤ 26.67, so c can be 20, 21, 22, 23, 24, 25, or 26: seven values.
Common wrong answers
- If you answered 6
- 6 leaves out one endpoint.
- If you answered 8
- 8 wrongly includes 27, which costs $810.
- If you answered 20
- 20 is the smallest number of chairs, not the count of options.
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