AlgebraHardLargest width under a perimeter limit
Algebra practice question
A rectangle has width w and a length three times its width. Its perimeter must be at most 64. What is the largest possible value of w?
Answer: 8
The perimeter is 2(w + 3w) = 8w, and 8w ≤ 64 gives w ≤ 8.
Common wrong answers
- If you answered 4
- 4 uses 16w ≤ 64.
- If you answered 16
- 16 uses a perimeter of 2(w + w) = 4w.
- If you answered 21.33
- 21.33 uses 3w ≤ 64.
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