AlgebraVery hardGreatest width under a length condition
Algebra practice question
A rectangle has a perimeter of 60 centimetres, and its length is at least twice its width. What is the greatest possible width of the rectangle, in centimetres?
Answer: 10
l = 30 − w and l ≥ 2w give 30 − w ≥ 2w, so w ≤ 10.
Common wrong answers
- If you answered 5
- 5 uses a perimeter of 30.
- If you answered 15
- 15 ignores the length condition.
- If you answered 20
- 20 is the length when the width is 10.
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