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AlgebraMediumCoffee blend mixture

Algebra practice question

A roaster blends beans costing $9 per kilogram with beans costing $14 per kilogram to make 10 kilograms of a blend worth $11 per kilogram. How many kilograms of the $14 beans are in the blend?

Answer: 4

The blend is worth 10 · 11 = $110. With t kilograms at $14 and (10 − t) at $9: 90 + 5t = 110, so t = 4.

Common wrong answers

If you answered 5
An even split would price the blend at $11.50; the actual mix is 6 kg and 4 kg.
If you answered 6
6 kilograms is the amount of the $9 beans; the $14 beans make up 4 kg.
If you answered 20
20 is the dollar gap 110 − 90; divide by the $5-per-kg difference to get 4 kg.

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