16Hit1600
AlgebraVery hardRecognising a system with no solution

Algebra practice question

Which of the following systems of equations has NO solution?

  1. A. 2x − y = 5 and 6x − 3y = 4Correct
  2. B. 2x − y = 5 and 6x − 3y = 15
  3. C. 2x − y = 5 and 2x + y = 5
  4. D. 2x − y = 5 and x + 3y = 4

Answer: A. 2x − y = 5 and 6x − 3y = 4

In choice A, the left sides are proportional (6x − 3y is 3 times 2x − y) but the right sides are not (4 is not 3 × 5). The lines are parallel and distinct, so they never meet.

Why the other answers are wrong

B. 2x − y = 5 and 6x − 3y = 15
6x − 3y = 15 is exactly 3 times 2x − y = 5 — the same line, so infinitely many solutions.
C. 2x − y = 5 and 2x + y = 5
These lines have slopes 2 and −2, so they cross once: (2.5, 0).
D. 2x − y = 5 and x + 3y = 4
These lines have slopes 2 and −1/3, so they cross once.

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