AlgebraVery hardRecognising a system with no solution
Algebra practice question
Which of the following systems of equations has NO solution?
- A. 2x − y = 5 and 6x − 3y = 4Correct
- B. 2x − y = 5 and 6x − 3y = 15
- C. 2x − y = 5 and 2x + y = 5
- D. 2x − y = 5 and x + 3y = 4
Answer: A. 2x − y = 5 and 6x − 3y = 4
In choice A, the left sides are proportional (6x − 3y is 3 times 2x − y) but the right sides are not (4 is not 3 × 5). The lines are parallel and distinct, so they never meet.
Why the other answers are wrong
- B. 2x − y = 5 and 6x − 3y = 15
- 6x − 3y = 15 is exactly 3 times 2x − y = 5 — the same line, so infinitely many solutions.
- C. 2x − y = 5 and 2x + y = 5
- These lines have slopes 2 and −2, so they cross once: (2.5, 0).
- D. 2x − y = 5 and x + 3y = 4
- These lines have slopes 2 and −1/3, so they cross once.
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