AlgebraMediumInequality for a minimum score
Algebra practice question
A student's marks on three tests were 72, 85, and 78. The student wants an average of at least 80 across four tests. Which inequality gives the possible marks m on the fourth test?
- A. (72 + 85 + 78 + m)/4 ≥ 80Correct
- B. (72 + 85 + 78 + m)/4 ≤ 80
- C. 72 + 85 + 78 + m ≥ 80
- D. (72 + 85 + 78)/3 + m ≥ 80
Answer: A. (72 + 85 + 78 + m)/4 ≥ 80
The average of four marks is their sum over 4, and 'at least 80' means ≥ 80. (This gives m ≥ 85.)
Why the other answers are wrong
- B. (72 + 85 + 78 + m)/4 ≤ 80
- 'At least' means ≥, not ≤.
- C. 72 + 85 + 78 + m ≥ 80
- Forgets to divide by 4.
- D. (72 + 85 + 78)/3 + m ≥ 80
- Averages three marks and then adds the fourth, which is not the four-test average.
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