AlgebraVery hardInequality with two variables from a budget
Algebra practice question
A florist has a budget of $120 for roses at $3 each and lilies at $4 each, and needs at least 10 lilies. If r roses and l lilies are bought, which system represents these constraints?
- A. 3r + 4l ≤ 120 and l ≥ 10Correct
- B. 3r + 4l ≥ 120 and l ≥ 10
- C. 3r + 4l ≤ 120 and l ≤ 10
- D. 4r + 3l ≤ 120 and l ≥ 10
Answer: A. 3r + 4l ≤ 120 and l ≥ 10
Cost 3r + 4l cannot exceed 120; lilies must be at least 10.
Why the other answers are wrong
- B. 3r + 4l ≥ 120 and l ≥ 10
- ≥ 120 would require spending at least the budget.
- C. 3r + 4l ≤ 120 and l ≤ 10
- l ≤ 10 caps lilies instead of requiring them.
- D. 4r + 3l ≤ 120 and l ≥ 10
- Swaps the prices.
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