AlgebraVery hardValue of a constant so a point lies on a line
Algebra practice question
In the xy-plane, the line with equation kx − 3y = 12 passes through the point (2, −2). What is the value of k?
Answer: 3
Substitute: 2k + 6 = 12, so 2k = 6 and k = 3.
Common wrong answers
- If you answered 6
- 6 is 2k, not k.
- If you answered 9
- 9 comes from 2k − 6 = 12 (wrong sign on the y term: −3 × −2 = +6).
- If you answered -3
- −3 has the wrong sign.
More Algebra questions
- Very hard
For what value of c does the system 3x − 2y = 8 and 9x + cy = 5 have no solution? - Very hard
In the system 5x + 4y = 32 and 3x − 2y = 6, what is the value of 8x + 2y? - Very hard
The solution set of the inequality |ax − b| ≤ 6, where a and b are constants and a > 0, is 3 ≤ x ≤ 9. What is … - Very hard
The function f is linear, and for every value of x, f(x + 2) − f(x) = 6. If f(5) = 4, what is the value of f(0… - Very hard
In the system of equations 2x + 3y = 12 and 5x − 2y = k, where k is a constant, the solution (x, y) satisfies … - Very hard
In the xy-plane, the system of equations kx + 6y = 12 and 2x + (k − 1)y = 6, where k is a constant, has infini…
Not affiliated with the College Board. SAT is a trademark of the College Board.