16Hit1600
AlgebraVery hardBuild and solve fractional linear equation from context

Algebra practice question

A hydroponic farm begins the week with t liters of nutrient solution in a holding tank. On Monday the farm used 1/4 of the solution in the tank. On Tuesday the farm used 1/3 of the solution that remained in the tank. The farm then added 90 liters of new solution, after which the tank held 6 liters more solution than it had held at the start of the week.

What is the value of t?

  1. A. 84
  2. B. 144
  3. C. 168Correct
  4. D. 192

Answer: C. 168

After Monday, (3/4)t liters remain. Tuesday's use removes 1/3 of that remainder, leaving (2/3)(3/4)t = (1/2)t. Adding 90 gives (1/2)t + 90 = t + 6, so 84 = (1/2)t and t = 168. Check: 168 - 42 = 126; 126 - 42 = 84; 84 + 90 = 174 = 168 + 6. (A) 84 is the volume left after Tuesday's use: the student correctly reaches (1/2)t = 84 but reports 84 instead of solving for t. (B) 144 comes from taking Tuesday's 1/3 of the ORIGINAL amount rather than of the remainder, giving (5/12)t + 90 = t + 6. (D) 192 comes from reading '6 liters more' as 6 liters less, giving (1/2)t + 90 = t - 6.

Why the other answers are wrong

A. 84
84 is the amount left in the tank after Tuesday's use — you correctly got (1/2)t = 84, but the question asks for t, so double it to 168.
B. 144
You took Tuesday's 1/3 out of the original t instead of out of what remained after Monday; that gives (5/12)t + 90 = t + 6 and 144. Tuesday's fraction applies to the (3/4)t still in the tank.
D. 192
You set up (1/2)t + 90 = t - 6, reading the ending amount as 6 liters *less* than the start. The tank ends with 6 liters more, so the right side is t + 6.

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