AlgebraVery hardFind parameter making a linear equation have no solution
Algebra practice question
A sign at a train museum's exhibit on railway mathematics poses the following puzzle, where k is a constant: 6(2x + 5) - 4x = 3(kx - 2) + 11x. The sign states that the equation has no solution.
What is the value of k?
- A. -3
- B. -1Correct
- C. 1
- D. 8/3
Answer: B. -1
The left side simplifies to 12x + 30 - 4x = 8x + 30. The right side simplifies to 3kx - 6 + 11x = (3k + 11)x - 6. An equation of the form ax + b = cx + d has no solution exactly when a = c and b is not equal to d. Setting 3k + 11 = 8 gives 3k = -3, so k = -1; the constants 30 and -6 differ, so there is indeed no solution. (A) -3 results from failing to distribute the 3 to the kx term, solving k + 11 = 8. (C) 1 results from a sign error when solving 3k = -3, treating it as 3k = 3. (D) 8/3 results from ignoring the separate 11x term on the right and solving 3k = 8.
Why the other answers are wrong
- A. -3
- You solved k + 11 = 8, which means the 3 in 3(kx - 2) never got distributed to the kx term. Distributing gives 3kx, so the coefficient equation is 3k + 11 = 8.
- C. 1
- Your setup was right, but 3k = -3 gives k = -1, not 1 — check the sign when you divide.
- D. 8/3
- You set 3k = 8, ignoring the separate 11x on the right side. The full right-side coefficient of x is 3k + 11, and that must equal 8.
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