AlgebraMediumHeads and legs
Algebra practice question
A field holds ducks and cows, 26 animals in all, with a total of 68 legs. How many cows are in the field?
Answer: 8
d + c = 26 and 2d + 4c = 68. Substituting d = 26 − c: 52 − 2c + 4c = 68 → 2c = 16 → c = 8.
Common wrong answers
- If you answered 13
- 13 assumes equal numbers.
- If you answered 17
- 17 is 68 ÷ 4, as if every animal were a cow.
- If you answered 18
- 18 is the number of ducks.
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