16Hit1600
AlgebraMediumHeads and legs

Algebra practice question

A field holds ducks and cows, 26 animals in all, with a total of 68 legs. How many cows are in the field?

Answer: 8

d + c = 26 and 2d + 4c = 68. Substituting d = 26 − c: 52 − 2c + 4c = 68 → 2c = 16 → c = 8.

Common wrong answers

If you answered 13
13 assumes equal numbers.
If you answered 17
17 is 68 ÷ 4, as if every animal were a cow.
If you answered 18
18 is the number of ducks.

More Algebra questions

Not affiliated with the College Board. SAT is a trademark of the College Board.