AlgebraMediumGreatest number of higher-priced tickets within a budget
Algebra practice question
Cinema tickets cost $9 for adults and $6 for children. A group of 12 people has at most $90 to spend on tickets. What is the greatest number of adults that can be in the group?
Answer: 6
9a + 6(12 − a) ≤ 90 → 3a + 72 ≤ 90 → a ≤ 6.
Common wrong answers
- If you answered 5
- 5 undercounts; 6 adults and 6 children cost exactly $90.
- If you answered 10
- 10 comes from 9a ≤ 90, ignoring the children's tickets.
- If you answered 12
- 12 adults would cost $108.
More Algebra questions
- Medium
A system: 2x + y = 11 and x − y = 1. What is the value of x + y? - Medium
Which of the following describes all solutions to 4x − 9 ≤ 2x + 5? - Medium
A phone's battery percentage is modeled by P = 100 − 8t, where t is the number of hours since it was unplugged… - Medium
If y = 2x − 1 and 3x + y = 14, what is the value of x? - Medium
If |2x − 3| = 7, what is the sum of all possible values of x? - Medium
Line k has equation y = (2/3)x + 1. Which equation represents a line perpendicular to line k?
Not affiliated with the College Board. SAT is a trademark of the College Board.