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AlgebraMediumChairs and a table

Algebra practice question

Four chairs and a table cost $340. The table costs $40 more than two chairs. What is the cost of one chair, in dollars?

Answer: 50

Let a chair cost c; the table costs 2c + 40. Then 4c + 2c + 40 = 340 → 6c = 300 → c = 50.

Common wrong answers

If you answered 85
85 is 340 ÷ 4, ignoring the table.
If you answered 140
140 is the table.
If you answered 56.67
56.67 comes from 6c = 340.

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