AlgebraVery hardMeeting point with a perpendicular through a given point
Algebra practice question
In the xy-plane, line ℓ has equation y = 2x + 1. Line m is perpendicular to ℓ and passes through (0, 5). What is the x-coordinate of the point where ℓ and m intersect?
Answer: 1.6 or 8/5
m has slope −1/2 and y-intercept 5: y = −x/2 + 5. Solving 2x + 1 = −x/2 + 5 gives 5x/2 = 4, so x = 8/5.
Common wrong answers
- If you answered 2
- 2 uses slope −1 for m instead of −1/2.
- If you answered 4
- 4 solves 2x + 1 = −x/2 + 5 without dividing by 5/2.
- If you answered -4
- −4 uses a parallel line of slope 2 through (0, 5), which never meets ℓ; the sign is a guess.
More Algebra questions
- Very hard
For what value of c does the system 3x − 2y = 8 and 9x + cy = 5 have no solution? - Very hard
In the system 5x + 4y = 32 and 3x − 2y = 6, what is the value of 8x + 2y? - Very hard
The solution set of the inequality |ax − b| ≤ 6, where a and b are constants and a > 0, is 3 ≤ x ≤ 9. What is … - Very hard
The function f is linear, and for every value of x, f(x + 2) − f(x) = 6. If f(5) = 4, what is the value of f(0… - Very hard
In the system of equations 2x + 3y = 12 and 5x − 2y = k, where k is a constant, the solution (x, y) satisfies … - Very hard
In the xy-plane, the system of equations kx + 6y = 12 and 2x + (k − 1)y = 6, where k is a constant, has infini…
Not affiliated with the College Board. SAT is a trademark of the College Board.