16Hit1600
AlgebraVery hardAges from a sum and a past relationship

Algebra practice question

The ages of a mother and her daughter add up to 32. Four years ago, the mother was twice as old as the daughter. How old is the mother now?

Answer: 20

m + d = 32 and m − 4 = 2(d − 4). The second gives m = 2d − 4; substituting, 3d − 4 = 32, so d = 12 and m = 20.

Common wrong answers

If you answered 12
12 is the daughter's age.
If you answered 16
16 is the mother's age four years ago.
If you answered 24
24 comes from m = 2d without the four-year shift.

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