Advanced MathMediumSolving quadratics by factoring
Advanced Math practice question
What are the solutions to x² + 6x + 8 = 0?
- A. x = 2 and x = 4
- B. x = −2 and x = −4Correct
- C. x = −1 and x = −8
- D. x = 1 and x = 8
Answer: B. x = −2 and x = −4
Find two numbers that multiply to +8 and add to +6: those are −2 and −4, so (x + 2)(x + 4) = 0 and x = −2 or x = −4. The trap is choice A, taking the factors 2 and 4 as the roots without flipping their signs.
Why the other answers are wrong
- A. x = 2 and x = 4
- You found the factor pair 2 and 4 correctly but forgot to flip the signs — (x + 2)(x + 4) = 0 means x = −2 and x = −4.
- C. x = −1 and x = −8
- The numbers −1 and −8 multiply to +8 but add to −9, not the +6 the middle term requires; you need −2 and −4.
- D. x = 1 and x = 8
- 1 and 8 multiply to 8, but they add to 9 rather than 6, and the roots of (x + 2)(x + 4) = 0 must be negative anyway.
More Advanced Math questions
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The system y = x² and y = x + 6 has two solutions. What is the sum of the two x-values of those solutions?
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