Advanced MathVery hardConverting to vertex form
Advanced Math practice question
The function f(x) = x² + 6x + 5 is rewritten in the form f(x) = (x + a)² + b. What is the value of b?
- A. b = 5
- B. b = −4Correct
- C. b = 9
- D. b = 14
Answer: B. b = −4
Complete the square: x² + 6x + 5 = (x² + 6x + 9) − 9 + 5 = (x + 3)² − 4, so a = 3 and b = −4. The trap is choice A, leaving b as the original constant 5 without accounting for the −9 added to complete the square.
Why the other answers are wrong
- A. b = 5
- You kept the original constant 5 as b, but completing the square adds 9 inside the parentheses, so you must subtract 9: 5 − 9 = −4.
- C. b = 9
- 9 is the number you add to make x² + 6x a perfect square, not the leftover constant. After writing (x + 3)², subtract that 9 back out: 5 − 9 = −4.
- D. b = 14
- You added 9 to the constant instead of subtracting it: 5 + 9 = 14. Since you inserted 9 to build (x + 3)², it has to come back off, giving 5 − 9 = −4.
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