AlgebraEasy–MediumTemperature after a fixed number of cooling intervals
Algebra practice question
A liquid cools at a steady rate, losing 3°C every 5 minutes. It starts at 95°C. What is its temperature, in degrees Celsius, after 25 minutes?
Answer: 80
25 minutes is 5 intervals of 5 minutes, so it loses 5 × 3 = 15°C: 95 − 15 = 80.
Common wrong answers
- If you answered 20
- 20 comes from 95 − 3 × 25, losing 3°C every minute.
- If you answered 70
- 70 loses 5°C per interval instead of 3.
- If you answered 92
- 92 subtracts 3 only once.
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