Problem-Solving and Data AnalysisMediumStatistics: mean, median, range
Problem-Solving and Data Analysis practice question
Data set: 5, 8, 8, 10, 14, 15
What is the difference between the mean and the median of this data set?
- A. 0
- B. 1Correct
- C. 2
- D. 3
Answer: B. 1
Mean = (5+8+8+10+14+15)/6 = 60/6 = 10. With six values, the median is the average of the 3rd and 4th: (8+10)/2 = 9. Difference = 10 − 9 = 1. The trap is taking a single middle value instead of averaging the two middles in an even-sized set.
Why the other answers are wrong
- A. 0
- You landed on a median of 10 by taking a single middle value; with six values the median is the average of the 3rd and 4th, (8 + 10)/2 = 9, so the difference from the mean of 10 is 1.
- C. 2
- You used 8, the 3rd value, as the median; in an even-sized set you average the two middle values: (8 + 10)/2 = 9, giving 10 − 9 = 1.
- D. 3
- No single slip in the mean or median produces 3 here — compute mean = 60/6 = 10 and median = (8 + 10)/2 = 9, and the difference is 1.
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