16Hit1600
Problem-Solving and Data AnalysisVery hardAt least one six in three rolls

Problem-Solving and Data Analysis practice question

A fair six-sided die is rolled three times. What is the probability that at least one of the rolls shows a six?

Answer: 91/216

P(no six in three rolls) = (5/6)³ = 125/216, so P(at least one six) = 1 − 125/216 = 91/216.

Common wrong answers

If you answered 1/2
1/2 adds 1/6 three times, which overcounts rolls with more than one six.
If you answered 1/216
1/216 is the probability of three sixes.
If you answered 125/216
125/216 is the probability of no sixes at all.

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