Advanced MathVery hardInterval where a quadratic is negative
Advanced Math practice question
For which values of x is p(x) = x² − 8x + 7 negative?
- A. 1 < x < 7Correct
- B. x < 1 or x > 7
- C. −7 < x < −1
- D. 0 < x < 8
Answer: A. 1 < x < 7
p(x) = (x − 1)(x − 7), which is negative between its zeros.
Why the other answers are wrong
- B. x < 1 or x > 7
- That is where p(x) is positive.
- C. −7 < x < −1
- The zeros are 1 and 7, not −1 and −7.
- D. 0 < x < 8
- 0 and 8 give p = 7, which is positive.
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