16Hit1600
Advanced MathHardExponential growth modeling

Advanced Math practice question

An investment of $1,000 grows at 6% per year, compounded annually. Which expression gives its value after t years?

  1. A. 1000(0.06)^t
  2. B. 1000(1.06)^tCorrect
  3. C. 1000(6)^t
  4. D. 1000 + (1.06)^t

Answer: B. 1000(1.06)^t

Growing 6% per year means each year the value is multiplied by 1 + 0.06 = 1.06, giving 1000(1.06)^t. The trap is choice A, using 0.06 as the growth factor — that would shrink the investment by 94% each year instead of growing it.

Why the other answers are wrong

A. 1000(0.06)^t
You used 0.06 as the multiplier, which would leave only 6% of the money each year; growing by 6% means multiplying by 1 + 0.06 = 1.06.
C. 1000(6)^t
You read "6%" as the number 6, so this multiplies the investment by 6 each year — a 500% annual increase rather than 6%.
D. 1000 + (1.06)^t
Compound growth multiplies the principal each year rather than adding to it; the 1000 must be a factor, not a separate added term.

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