16Hit1600
Advanced MathHardExponential decay

Advanced Math practice question

A car worth $20,000 loses 15% of its value each year. What is its value after 2 years?

  1. A. $14,000
  2. B. $14,450Correct
  3. C. $17,000
  4. D. $14,700

Answer: B. $14,450

Losing 15% means retaining 85% each year: 20000 × 0.85 × 0.85 = 20000 × 0.7225 = $14,450. Choice A wrongly subtracts a flat 30%; decay compounds, it doesn't add up.

Why the other answers are wrong

A. $14,000
You subtracted a flat 30% (15% twice off the original $20,000). Percent decay compounds: the second year's 15% comes off $17,000, not $20,000.
C. $17,000
That's the value after just one year: 20000 × 0.85 = 17000. You need to apply the 85% factor a second time to reach year 2.
D. $14,700
There's no standard slip that lands on $14,700 — the reliable method is to multiply by the retained fraction each year: 20000 × 0.85 × 0.85 = $14,450.

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