Advanced MathHardExponential functions
Advanced Math practice question
A population of bacteria doubles every 3 hours. If it starts at 500, which function models the population P after t hours?
- A. P = 500 · 2^(t/3)Correct
- B. P = 500 · 2^(3t)
- C. P = 500 · 3^(t/2)
- D. P = 500 + 2^(t/3)
Answer: A. P = 500 · 2^(t/3)
Doubling means base 2; 'every 3 hours' means the exponent counts how many 3-hour periods have passed, i.e. t/3. Choice B doubles every 1/3 hour — far too fast.
Why the other answers are wrong
- B. P = 500 · 2^(3t)
- You multiplied t by 3 instead of dividing. The exponent must count how many 3-hour periods have passed, which is t/3 — as written, your function doubles every 1/3 of an hour.
- C. P = 500 · 3^(t/2)
- You swapped the roles of the two numbers: 2 is the growth factor (doubling) and 3 is the time it takes, so 2 belongs in the base and 3 in the denominator of the exponent.
- D. P = 500 + 2^(t/3)
- Exponential growth multiplies the starting amount, not adds to it. With addition, 500 barely changes at first and never doubles — it should be 500 · 2^(t/3).
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