Advanced MathVery hardRadical equation with one valid root
Advanced Math practice question
What is the solution to the equation √(2x + 2) = x − 3?
Answer: 7
Square both sides: 2x + 2 = x² − 6x + 9, so x² − 8x + 7 = (x − 1)(x − 7) = 0. Check x = 1: √4 = 2 but 1 − 3 = −2 — rejected. Check x = 7: √16 = 4 = 7 − 3 ✓. So x = 7.
Common wrong answers
- If you answered 1
- 1 is the extraneous root: it makes the right side −2, but a square root is never negative.
- If you answered 3
- 3 makes the right side 0 but the left side √8.
- If you answered -1
- −1 makes the radicand 0 and the right side −4; not a solution.
More Advanced Math questions
- Very hard
The function f(x) = x² + 6x + 5 is rewritten in the form f(x) = (x + a)² + b. What is the value of b? - Very hard
What is the solution to the equation 6/(x − 2) = 3? - Very hard
The polynomial p(x) = x³ − 4x has how many distinct real zeros? - Very hard
The polynomial p is defined by p(x) = x³ + ax² + bx − 12, where a and b are constants. If x − 2 is a factor of… - Very hard
The function f, defined by f(x) = 3000(1.331)^(x/12), gives the value, in dollars, of an investment x months a… - Very hard
In the xy-plane, the parabola y = x² − 4x + 7 and the line y = mx − 2, where m is a constant, intersect at exa…
Not affiliated with the College Board. SAT is a trademark of the College Board.