Advanced MathVery hardChoosing the system that models a problem
Advanced Math practice question
A rectangular garden has a perimeter of 30 metres and an area of 50 square metres. Which system could be used to find its length L and width W?
- A. 2L + 2W = 30 and LW = 50Correct
- B. L + W = 30 and LW = 50
- C. 2L + 2W = 30 and L + W = 50
- D. LW = 30 and 2L + 2W = 50
Answer: A. 2L + 2W = 30 and LW = 50
Perimeter is 2L + 2W; area is LW.
Why the other answers are wrong
- B. L + W = 30 and LW = 50
- L + W = 30 would be half the perimeter, but the perimeter is 30.
- C. 2L + 2W = 30 and L + W = 50
- L + W = 50 misreads the area as a sum.
- D. LW = 30 and 2L + 2W = 50
- Swaps perimeter and area.
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