Advanced MathVery hardAdding rational expressions
Advanced Math practice question
For x ≠ 0 and x ≠ −1, which expression is equivalent to 1/x + 1/(x + 1)?
- A. (2x + 1) / (x(x + 1))Correct
- B. 2 / (2x + 1)
- C. 1 / (x(x + 1))
- D. (2x + 1) / (x + 1)
Answer: A. (2x + 1) / (x(x + 1))
Use the common denominator x(x + 1). Rewrite each fraction: 1/x = (x + 1)/(x(x + 1)) and 1/(x + 1) = x/(x(x + 1)). Add the numerators: (x + 1) + x = 2x + 1, over x(x + 1).
Why the other answers are wrong
- B. 2 / (2x + 1)
- You added the numerators together and the denominators together. Fractions can't be added that way — they need a common denominator first.
- C. 1 / (x(x + 1))
- The denominator is right but the numerators were multiplied (1 × 1) instead of added after being rewritten: (x + 1) + x = 2x + 1.
- D. (2x + 1) / (x + 1)
- The numerator is right, but the common denominator is the PRODUCT x(x + 1), not just x + 1. The first fraction's x is missing from the bottom.
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