Advanced MathVery hardConsecutive integers from the sum of their reciprocals
Advanced Math practice question
The sum of the reciprocals of two consecutive positive integers is 7/12. What is the smaller of the two integers?
Answer: 3
1/n + 1/(n + 1) = 7/12 → 12(2n + 1) = 7n(n + 1) → 7n² − 17n − 12 = 0 → (7n + 4)(n − 3) = 0. Since n is a positive integer, n = 3. Check: 1/3 + 1/4 = 7/12.
Common wrong answers
- If you answered 4
- 4 is the larger integer.
- If you answered 7
- 7 is the numerator of the sum.
- If you answered 12
- 12 is the denominator of the sum, not an integer in the pair.
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