Advanced MathVery hardConstant for which a line is tangent to a circle
Advanced Math practice question
In the xy-plane, the line y = x + k is tangent to the circle x² + y² = 8, where k is a positive constant. What is the value of k?
Answer: 4
Substitute: x² + (x + k)² = 8 → 2x² + 2kx + k² − 8 = 0. Tangency means one solution, so the discriminant is 0: 4k² − 8(k² − 8) = 0 → k² = 16 → k = 4.
Common wrong answers
- If you answered 8
- 8 is the constant in the circle's equation, not k.
- If you answered 16
- 16 is k², before taking the square root.
- If you answered 2.83
- 2.83 is √8, the radius, which is not the y-intercept of the tangent line.
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