16Hit1600
Advanced MathHardWriting a half-life model

Advanced Math practice question

A patient takes a 60-milligram dose of a medicine. The amount of the medicine in the bloodstream halves every 4 hours. Which function gives the amount A(t), in milligrams, remaining t hours after the dose?

  1. A. A(t) = 60(1/2)^(t/4)Correct
  2. B. A(t) = 60(1/2)^(4t)
  3. C. A(t) = 60(2)^(t/4)
  4. D. A(t) = 60 − 7.5t

Answer: A. A(t) = 60(1/2)^(t/4)

Each 4-hour period multiplies the amount by 1/2, and t hours contain t/4 such periods. So A(t) = 60(1/2)^(t/4). Check: after 8 hours, 60(1/2)² = 15.

Why the other answers are wrong

B. A(t) = 60(1/2)^(4t)
(1/2)^(4t) halves the amount four times every hour — far too fast. It should halve once every 4 hours, so the exponent is t/4.
C. A(t) = 60(2)^(t/4)
A base of 2 makes the amount DOUBLE every 4 hours. The medicine is being cleared, so the base is 1/2.
D. A(t) = 60 − 7.5t
A linear model loses the same 7.5 mg every hour and reaches zero at 8 hours. Halving is exponential: the amount lost shrinks each period.

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