Advanced MathHardMaximum height and when it occurs
Advanced Math practice question
The height, in feet, of a ball t seconds after it is thrown is given by h(t) = −16t² + 64t. What is the maximum height the ball reaches?
- A. 64 feetCorrect
- B. 2 feet
- C. 128 feet
- D. 4 feet
Answer: A. 64 feet
The vertex is at t = −64/(2 × −16) = 2, and h(2) = −64 + 128 = 64.
Why the other answers are wrong
- B. 2 feet
- 2 is the TIME of the maximum, not the height.
- C. 128 feet
- 128 is 64 × 2, the first term's value at t = 2 without the −16t² part.
- D. 4 feet
- 4 is when the ball lands (h = 0).
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