Advanced MathHardPoint on a line at a given distance from the origin
Advanced Math practice question
In the xy-plane, the point (x, 2x), where x > 0, is at a distance of 5√5 from the origin. What is the value of x?
Answer: 5
Distance² = x² + (2x)² = 5x² = (5√5)² = 125 → x² = 25 → x = 5.
Common wrong answers
- If you answered 25
- 25 is x², not x.
- If you answered 125
- 125 is the square of the distance.
- If you answered -5
- −5 is ruled out by x > 0.
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